What is the derivative of #y= ln(1 + e^(2x))#?
Christopher AgrestaThe derivative is
Finally
By signing up, you agree to our Terms of Service and Privacy Policy
Isaiah AllenThe derivative of y = ln(1 + e^(2x)) with respect to x is:
dy/dx = (2e^(2x)) / (1 + e^(2x))
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do I differentiate #y=ln(sec(x) tan(x))#?
- What is the derivative of #7xy#?
- How do you implicitly differentiate #-y= x^3y^2-x^2y^3-2xy^4 #?
- How do you find the first and second derivatives of #y=(2x^4-3x)/(4x-1)# using the quotient rule?
- How do you differentiate #f(x) = (2x+1)^7# using the chain rule?
- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7