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What is the derivative of this function #y=29/4cot^-1((2x)/3)#?

Answer 1

Ezekiel Alexander

the answer
#y'=-(58)/[12[1+((2x)/3)^2]]#

show below:

#y=cot^-1(x)#

#y'=[-1*x']/(1+(x)^2)#

#y=29/4cot^-1((2x)/3)#

#y'=29/4*-(2/3)/[1+((2x)/3)^2]#

#y'=-(58/12)/[1+((2x)/3)^2]#

#y'=-(58)/[12[1+((2x)/3)^2]]#

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Answer 2

Adam Adkins

The derivative of the function ( y = \frac{29}{4}\cot^{-1}\left(\frac{2x}{3}\right) ) is ( \frac{-29}{6(1 + \left(\frac{2x}{3}\right)^2)} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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