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What is the derivative of #sqrt(e^(2x) +e^(-2x))#?

Answer 1

Elijah Abram

#1/2(e^(2x)+e^(-2x))^(-1/2)*(2e^(2x)-2e^(-2x))#

We may apply the power rule to obtain :

#d/dxsqrt(e^(2x)+e^(-2x))=d/dx(e^(2x)+e^(-2x))^(1/2)#

#=1/2(e^(2x)+e^(-2x))^(-1/2)*(2e^(2x)-2e^(-2x))#

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Answer 2

Elijah Abram

The derivative of √(e^(2x) + e^(-2x)) is (2e^(2x) - 2e^(-2x))/(2√(e^(2x) + e^(-2x))).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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