What is the derivative of #log(8x-1)#?
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The derivative of log(8x - 1) with respect to x is 8 / (8x - 1).
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The derivative of log(8x - 1) with respect to x is:
[ \frac{d}{dx} \left[ \log(8x - 1) \right] = \frac{1}{8x - 1} \cdot \frac{d}{dx} (8x - 1) ]
[ = \frac{1}{8x - 1} \cdot 8 = \frac{8}{8x - 1} ]
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The derivative of log(8x-1) is 8/(8x-1).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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