What is the derivative of #g(x)=x+(4/x)#?

Answer 1

#g'(x) = 1-4/(x^2)#

To find the derivative of #g(x)#, you must differentiate each term in the sum
#g'(x) = d/dx(x) + d/dx(4/x)#

It is easier to see the Power Rule on the second term by rewriting it as

#g'(x) = d/dx(x) + d/dx(4x^-1)#
#g'(x) = 1 + 4d/dx(x^-1)#
#g'(x) = 1 + 4(-1x^(-1-1))#
#g'(x) = 1 + 4(-x^(-2))#
#g'(x) = 1 - 4x^-2#

Finally, you can rewrite this new second term as a fraction:

#g'(x) = 1-4/(x^2)#
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Answer 2

#g'(x)=1-4/(x^2)#

What might be daunting is the #4/x#. Luckily, we can rewrite this as #4x^-1#. Now, we have the following:
#d/dx (x+4x^-1)#

We can use the Power Rule here. The exponent comes out front, and the power gets decremented by one. We now have

#g'(x)=1-4x^-2#, which can be rewritten as
#g'(x)=1-4/(x^2)#

Hope this helps!

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Answer 3

The derivative of ( g(x) = x + \frac{4}{x} ) is ( g'(x) = 1 - \frac{4}{x^2} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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