# What is the derivative of #f(t) = ((lnt)^2-t, t^2cost ) #?

# f'(t) = (2t^2cost - t^3sint) / (2lnt - t ) #

And,

And Also, By the chain rule:

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The derivative of ( f(t) = (\ln(t)^2 - t, t^2 \cos(t)) ) with respect to ( t ) is:

( f'(t) = \left(2\frac{\ln(t)}{t} - 1, 2t\cos(t) - t^2\sin(t)\right) )

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