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What is the derivative of #-2/(2x-4)^2#?

Answer 1

Ezra Adams

# d/dx -2/(2x-4)^2 =1/(x-2)^3 #

# d/dx -2/(2x-4)^2 = d/dx -2/((2(x-2))^2) # # " "= d/dx -2/(4(x-2)^2) # # " "= d/dx -1/2 (x-2)^(-2) #

So applying the power rule we get;

# d/dx -2/(2x-4)^2 = -1/2 (-2)(x-2)^(-3) # # " "= 1(x-2)^(-3) # # " "= 1/(x-2)^3 #

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Answer 2

Scarlett Allison

The derivative of -2/(2x-4)^2 is 8/(2x-4)^3.

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Answer 3

Luke Alvarez

The derivative of ( -\frac{2}{(2x-4)^2} ) is ( \frac{8}{(2x-4)^3} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.