What is the density of Freon-11 (CFCl3) at 166 degrees Celsius and 5.92 atm?

Answer 1

The density of Freon-11 is 22.6 g/L.

Freon-11 is a compound with formula #"CFCl"_3#. Its chemical name is trichlorofluoromethane.

We can use the Ideal Gas Law to determine its density.

#color(blue)(bar(ul(|color(white)(a/a)pV = nRTcolor(white)(a/a)|)))" "#
Since #n = m/M#, we can substitute this to get
#pV = (m/M)RT#

We can rearrange this to

#pM = m/VRT#
But #"density"= "mass"/"volume"# or #color(brown)(bar(ul(|color(white)(a/a)ρ = m/Vcolor(white)(a/a)|)))" "#
∴ #pM = ρRT#

and

#color(brown)(bar(ul(|color(white)(a/a)ρ = (pM)/(RT)color(white)(a/a)|)))" "#

In your problem,

#p = "5.92 atm"# #M = "137.37 g/mol"# #R = "0.082 06 L·atm·K"^"-1""mol"^"-1"# #T = "166 °C" = "439.15 K"#
∴ #ρ = (5.92color(red)(cancel(color(black)("atm"))) × 137.37color(white)(l) "g"·color(red)(cancel(color(black)("mol"^"-1"))))/("0.082 06 L"·color(red)(cancel(color(black)("atm·K"^"-1""mol"^"-1"))) × 439.15color(red)(cancel(color(black)("K")))) = "22.6 g/L"#
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Answer 2

To calculate the density of Freon-11 (CFCl3) at 166 degrees Celsius and 5.92 atm, you can use the ideal gas law. The molar mass of CFCl3 is 137.37 g/mol. The ideal gas law equation is: [PV = nRT] where: P = pressure (in atm) V = volume (in liters) n = number of moles R = ideal gas constant (0.0821 L·atm/mol·K) T = temperature (in Kelvin) To find the number of moles, use the formula: [n = \frac{PV}{RT}] Then, to find the density, use the formula: [Density = \frac{mass}{volume}] [mass = n \times \text{molar mass of CFCl3}] [volume = \frac{RT}{P}] Substitute the values into the formulas and solve for density.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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