What is the cross product of #(4 i + 4 j + 2 k)# and #(-5i + 12j + 2 k)#?
Leo AbeytaI found:
I would use the matrix notation and evaluate the determinant:
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Nicholas AgrusaThe cross product of the vectors ( (4i + 4j + 2k) ) and ( (-5i + 12j + 2k) ) is:
[ \begin{vmatrix} i & j & k \ 4 & 4 & 2 \ -5 & 12 & 2 \end{vmatrix} ]
[ = i((4)(2) - (4)(2)) - j((4)(-5) - (2)(-5)) + k((4)(12) - (4)(-5)) ]
[ = 0i - (-20j) + 68k ]
[ = 20j + 68k ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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