What is the correct formula of an ionic compound containing Fe-2 and PO4-3 and how is it called?

Answer 1
The ionic formula is #Fe_3# # (P#O4#)_2#

The phosphate ion has a charge of -3 and the ferrous ion has a charge of +2. We can write the formula using the charge balance method.

Let's tally how many phosphate and ferrous ions are required to maintain the equilibrium between the total positive and negative charge.

Three x (+2) = +6 charge will result from having three ferrous ions. Two phosphate ions are required to have six units of negative charge because each phosphate ion has a charge of -3, so two x (-3) = -6.

iron (II) phosphate, or ferrous phosphate, is the resultant formula.

#Fe_3# # (P#O4# )_2#
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Answer 2

Fe3(PO4)2 is the correct formula for the ionic compound known as iron(II) phosphate, which contains Fe^2+ and PO4^3-.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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