What is the concentration of sodium ions in a solution obtained by dissolving #"3.25 g"# of sodium phosphate, #"Na"_3"PO"_4#, in enough water to make #"250.0 mL"# of solution?
Molar mass of #"Na"_3"PO"_4: "163.9 g/mol"#
Molar mass of
The idea here is that you need to use the fact that all the moles of sodium phosphate that you dissolve to make this solution will dissociate to produce sodium cations to calculate the concentration of the sodium cations.
Use the molar mass of sodium phosphate to calculate the number of moles of salt used to make this solution.
This means that the number of moles of sodium cations present in this solution will be
You can thus say that the molarity of the solution is equal to
The answer is rounded to three sig figs, the number of sig figs you have for the mass of sodium phosphate.
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Calculate the molarity of sodium ions by finding moles of Na₃PO₄ and then using the formula: ( \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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