What is the concentration of silver(I) ion in a saturated solution of silver(I) carbonate containing 0.0024 M Na2CO3? For Ag2CO3, Ksp = 8.6 x 10^–12.

Answer 1

We address the equilibrium #Ag_2CO_3(s) rightleftharpoons2Ag^+ + CO_3^(2-)#

And so...#K_"sp"=[Ag^+]^2[CO_3^(2-)]#

We also possess the information needed for this expression.

#K_"sp"=8.6xx10^-12=[Ag^+]^2[CO_3^(2-)]#
#[Ag^+]=sqrt(K_"sp"/[[CO_3^(2-)]])#
We are given that #[CO_3^(2-)]=0.0024*mol*L^-1#.
And so...#[Ag^+]=sqrt((8.6xx10^-12)/(0.0024))=5.99xx10^-5*mol*L^-1#....
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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