What is the concentration of HF under these conditions (listed in details)?

For the reaction:
H2(g) + F2(g) ⇆ 2HF(g)
K = 2.1 × 10-3 at a certain temperature.
At equilibrium: [H2] = [F2] = 0.066 M

Answer 1

#[HF]=0.03M#

value of #K_c=2.1*10^-3# at temp. constt. At equilibrium: [H2] = [F2] = 0.066 M so, #K_c=[HF]^2/([H_2][F_2])# #2.1*10^-3=[HF]^2/(0.066*0.066)# #[HF]^2=2.1*10^-3*(0.066)^2# #[HF]^2=0.091476*10^-2=0.30/10=0.03M#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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What is the concentration of HF under these conditions (listed in details)?

For the reaction: H2(g) + F2(g) ⇆ 2HF(g) K = 2.1 × 10-3 at a certain temperature. At equilibrium: [H2] = [F2] = 0.066 M

For the reaction:
H2(g) + F2(g) ⇆ 2HF(g)
K = 2.1 × 10-3 at a certain temperature.
At equilibrium: [H2] = [F2] = 0.066 M