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What is the concentration of a 450 mL solution that contains 200 grams of iron (II) chloride?

Answer 1

Jeremiah Adams

#"Concentration"# #=# #"Moles of solute"/"Litres of solution"#

#"Moles of solute"# #=# #(200*g)/(126.75*g*mol^-1)# #=# #1.58*mol#

#"Concentration"# #=# #(1.58*mol)/(450xx10^-3*L)# #=# #3.5*mol*L^-1# with respect to #FeCl_2#.

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Answer 2

Naomi Aronson

To find the concentration of the solution, first calculate the number of moles of iron (II) chloride using its molar mass. Then, divide the number of moles by the volume of the solution in liters.

Calculate the molar mass of FeCl2: Fe (55.85 g/mol) + 2Cl (35.45 g/mol) = 55.85 + 2(35.45) = 126.75 g/mol
Determine the number of moles of FeCl2: 200 g / 126.75 g/mol ≈ 1.58 moles
Calculate the concentration: Concentration (in moles per liter) = 1.58 moles / (450 mL ÷ 1000) = 1.58 moles / 0.45 L ≈ 3.51 moles/L

So, the concentration of the solution is approximately 3.51 moles/L.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.