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What is the concentration if #.358# #g# of #NaNO_3# is present in #555# #mL# of water?

Answer 1

Wyatt Atkins

#7.59xx10^(-3) mol*L^-1# in sodium nitrate

Here, the formula for concentration is just (amount of substance)/(volume of solution).

So #(0.358*cancel(g))/(85.00*cancel(g)*mol^-1)# #xx# #1/(555xx10^(-3)*L)# #=# #??*mol*L^-1#

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Answer 2

Ellie Andrews

To find the concentration of NaNO3, you need to divide the mass of NaNO3 by the volume of water in liters. First, convert 555 mL to liters by dividing by 1000:

555 mL ÷ 1000 = 0.555 L

Then, divide the mass of NaNO3 (0.358 g) by the volume of water in liters (0.555 L) to find the concentration:

Concentration = Mass of NaNO3 / Volume of water Concentration = 0.358 g / 0.555 L ≈ 0.645 g/L

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.