# What is the circumference of the circle whose equation is #(x-9)^2+(y-3)^2=64#?

The circumference of circle

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The circumference of the circle with the equation ((x-9)^2 + (y-3)^2 = 64) is (2 \pi \times \text{radius}). In this equation, the radius is (\sqrt{64} = 8). Thus, the circumference is (2 \pi \times 8 = 16 \pi). Therefore, the circumference of the circle is (16 \pi).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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