What is the circumference and area in feet of circular pool that has a diameter of 20 yards?

Answer 1

#188.50 ft.# and #2,827.43ft.^2#

#diameter=2r=20# => #r=10yards# #1 yd.=3 ft.# #10yds.=30 ft.#
#Perimeter_circ=2pi*r=2pi*(30)=60pi ft.~=188.50 ft.#
#Area_circ=pi*r^2=pi*(30)^2=900pi ft.^2~=2,827.43 ft.^2#
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Answer 2

The circumference of a circular pool can be calculated using the formula ( C = \pi \times d ), where ( d ) is the diameter. Given that the diameter is 20 yards, we first convert it to feet (since 1 yard = 3 feet), so the diameter becomes ( 20 \times 3 = 60 ) feet.

[ C = \pi \times 60 \approx 188.5 \text{ feet} ]

The area of the circular pool can be calculated using the formula ( A = \pi \times r^2 ), where ( r ) is the radius. Given that the diameter is 20 yards, the radius is ( \frac{20}{2} = 10 ) yards. Converting 10 yards to feet, we get ( 10 \times 3 = 30 ) feet.

[ A = \pi \times 30^2 \approx 2827.43 \text{ square feet} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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