# What is the centroid of a triangle with corners at #(5, 2 )#, #(2, 5)#, and #(7,2)#?

(14/3,3).

The centroid's coordinates in any triangle are equal to the vertices' average coordinates.

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To find the centroid of a triangle with vertices at ((5, 2)), ((2, 5)), and ((7, 2)), you can use the following formula:

[ \text{Centroid} = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) ]

Substitute the coordinates of the vertices into this formula:

[ \text{Centroid} = \left( \frac{5 + 2 + 7}{3}, \frac{2 + 5 + 2}{3} \right) ]

[ \text{Centroid} = \left( \frac{14}{3}, \frac{9}{3} \right) ]

[ \text{Centroid} = \left( \frac{14}{3}, 3 \right) ]

So, the centroid of the triangle with vertices at ((5, 2)), ((2, 5)), and ((7, 2)) is (\left( \frac{14}{3}, 3 \right)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you find the equation of the perpendicular bisector of the segment joining the points A #(6, -3)# and B #(-2, 5)#?
- A line segment is bisected by a line with the equation # 8 y + 5 x = 4 #. If one end of the line segment is at #( 2 , 7 )#, where is the other end?

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