# What is the centroid of a triangle with corners at #(2, 7 )#, #(1,5 )#, and #(7 , 5 )#?

Centroid is

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To find the centroid of a triangle with vertices at ((2, 7)), ((1, 5)), and ((7, 5)), use the formula:

[ \text{Centroid} = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) ]

Substitute the coordinates of the vertices into the formula:

[ x_1 = 2, \quad y_1 = 7 ] [ x_2 = 1, \quad y_2 = 5 ] [ x_3 = 7, \quad y_3 = 5 ]

Calculate the centroid:

[ x_{\text{centroid}} = \frac{2 + 1 + 7}{3} = \frac{10}{3} ] [ y_{\text{centroid}} = \frac{7 + 5 + 5}{3} = \frac{17}{3} ]

So, the centroid of the triangle is (\left(\frac{10}{3}, \frac{17}{3}\right)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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