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What is the Cartesian form of #(9,(3pi )/4)#?

Answer 1

The Cartesian form of #(r,theta)=(9,(3pi)/4)# is #(x,y)=(-(9sqrt(2))/2,(9sqrt(2))/2)#.

Use the equations #x=rcos(theta)# and #y=rsin(theta)# to get #x=9cos((3pi)/4)=9 * -(sqrt(2))/2=-(9sqrt(2))/2# and #y=9sin((3pi)/4)=9 * (sqrt(2))/2=(9sqrt(2))/2#.

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Answer 2

Isaiah Allen

The Cartesian form of the point (9, (3π)/4) is (9cos((3π)/4), 9sin((3π)/4)). Simplifying, this becomes (-9√2/2, 9√2/2). Therefore, the Cartesian form is (-9√2/2, 9√2/2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.