# What is the Cartesian form of #(81,(3pi)/8)#?

We're asked to find the Cartesian (rectangular) form of a polar coordinate.

This is done by

Therefore,

The rectangular form is thus

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The Cartesian form of the point given in polar coordinates as ((81, \frac{3\pi}{8})) can be found using the formulas:

[x = r \cdot \cos(\theta)] [y = r \cdot \sin(\theta)]

where (r) is the radial distance and (\theta) is the angle in radians.

Substituting (r = 81) and (\theta = \frac{3\pi}{8}), we get:

[x = 81 \cdot \cos\left(\frac{3\pi}{8}\right)] [y = 81 \cdot \sin\left(\frac{3\pi}{8}\right)]

Now, evaluate the trigonometric functions:

[x \approx 57.31] [y \approx 57.31]

Therefore, the Cartesian form of the point ((81, \frac{3\pi}{8})) is approximately ((57.31, 57.31)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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