What is the Cartesian form of #( -8, (-7pi)/3 ) #?

Answer 1

#(-8,-7pi/3) to (-4, 4sqrt3)#

The conversion is #(r,theta) to (rcos(theta),rsin(theta))#
#(-8,-7pi/3) to (-8cos((-7pi)/3), -8sin((-7pi/3)))#
#(-8,-7pi/3) to (-8(0.5), -8(-sqrt3/2))#
#(-8,-7pi/3) to (-4, 4sqrt3)#
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Answer 2

To convert the point (-8, (-7π)/3) from polar coordinates to Cartesian coordinates, you can use the following formulas:

x = r * cos(θ) y = r * sin(θ)

Where r is the radius and θ is the angle in radians.

In this case, r = -8 and θ = (-7π)/3. Substituting these values into the formulas:

x = -8 * cos((-7π)/3) y = -8 * sin((-7π)/3)

Now, calculate the cosine and sine values for the given angles:

cos((-7π)/3) = cos(π/3) = 1/2 sin((-7π)/3) = sin(π/3) = √3/2

Substitute these values back into the formulas:

x = -8 * (1/2) = -4 y = -8 * (√3/2) = -4√3

So, the Cartesian form of the point (-8, (-7π)/3) is (-4, -4√3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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