What is the Cartesian form of #( -2, (-7pi)/8 ) #?

Answer 1

Cartesian coordinates are

#(x, y) \equiv(1.8477, 0.765)#

The cartesian coordinates #(x, y)# of the given point #(r, \theta)\equiv(-2, -{7\pi}/8)# are given as
#x=r\cos\theta#
#=-2\cos({-7pi}/8)#
#=2\cos({pi}/8)#
#=1.8477#
#y=r\sin\theta#
#=-2\sin({-7pi}/8)#
#=2\sin({pi}/8)#
#=0.765#

hence the cartesian coordinates are

#(x, y) \equiv(1.8477, 0.765)#
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Answer 2

Cartesian coordinates are #(1.8478,0.7654)#

For a polar form coordinates #(r,theta)#
Cartesian form is #(rcostheta,rsintheta)#
Hence, for #(-2,(-7pi)/8)#
Cartesian form is #(-2cos((-7pi)/8),-2sin((-7pi)/8))#
i.e. #(-2(-cos(pi/8)),-2(-sin(pi/8))#
and as #sin(pi/8)=1/2sqrt(2-sqrt2)=0.3827#
and #cos(pi/8)=1/2sqrt(2+sqrt2)=0.9239#
and Cartesian coordinates are #(1.8478,0.7654)#
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Answer 3

The Cartesian form of the point ( (-2, -\frac{7\pi}{8}) ) is ( (-2, -\frac{7}{8}\pi) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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