What is the Cartesian form of #(-17,(-3pi)/6))#?

Answer 1

#(0,17)#

To write a polar point into cartesian form, we convert it into the parametric form using these equations:

#x=rcostheta# #y=rsintheta#
#r=-17# and #theta=(-3pi)/6# Plug into these equations:
#x=-17cos(-pi/2)=0# #y=-17sin(-pi/2)=17#
So we have #x=0# and #y=17#. Write this as a point:
#(0,17)#
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Answer 2

The Cartesian form of a point given in polar coordinates ((r, \theta)) can be found using the formulas (x = r \cos(\theta)) and (y = r \sin(\theta)).

Given the polar coordinates ((-17,(-3\pi)/6)), we can calculate the Cartesian coordinates as follows:

  • (r = -17)
  • (\theta = (-3\pi)/6 = -\pi/2)

Using the conversion formulas:

  • (x = -17 \cos(-\pi/2) = -17 \cdot 0 = 0)
  • (y = -17 \sin(-\pi/2) = -17 \cdot (-1) = 17)

Therefore, the Cartesian form of the given polar coordinates is ((0, 17)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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