# What is the Cartesian form of #(-10,(-17pi)/16))#?

We're asked to find the Cartesian (rectangular) form of a given polar coordinate.

To do this, we use the equations

In this case,

So we have

The Cartesian coordinate is thus

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The Cartesian form of the point (-10, (-17π)/16) is (-10, -10.625).

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The Cartesian form of the point ((-10, -\frac{17\pi}{16})) can be found by converting from polar coordinates to rectangular coordinates using the formulas:

[ x = r \cos(\theta) ] [ y = r \sin(\theta) ]

where (r) is the radius and (\theta) is the angle in radians.

Given (r = -10) and (\theta = -\frac{17\pi}{16}), we can calculate:

[ x = -10 \cos\left(-\frac{17\pi}{16}\right) ] [ y = -10 \sin\left(-\frac{17\pi}{16}\right) ]

Then, compute the values of (x) and (y), which will give the Cartesian coordinates of the point.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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