What is the balanced equation of the reaction between gaseous propane and and oxygen gas?

Answer 1

The balanced equation for the reaction between gaseous propane (C3H8) and oxygen gas (O2) is:

C3H8 + 5O2 → 3CO2 + 4H2O

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Answer 2

The typical rigmarole is to....

#"(i) balance the carbon as carbon dioxide..."#
#"(ii) balance the hydrogens as water..."#
#"(iii) ...and THEN balance the oxygens......"#
And so we completely COMBUST propane, #C_3H_8#..
#"(i)"# #underbrace(C_3H_8(g) + O_2(g) rarr 3CO_2(g))_"carbons balanced" #
#"(ii)"# #underbrace(C_3H_8(g) + O_2(g) rarr 3CO_2(g)+4H_2O(l))_"carbons and hydrogens balanced" #
#"(iii)"# #underbrace(C_3H_8(g) + 5O_2(g) rarr 3CO_2(g)+4H_2O(l))_"the entire equation balanced" #

Now this works well for odd-numbered alkanes....for EVEN-NUMBERED alkanes...we reach a problem...

#underbrace(C_4H_10(g) + 13/2O_2(g))_"266 g" rarr underbrace(4CO_2(g) + 5H_2O(l))_"266 g"#

...OR....

#underbrace(2C_4H_10(g) + 13O_2(g))_"532 g" rarr underbrace(8CO_2(g) + 10H_2O(l))_"532 g"#

Sometimes the latter equation is preferred because if you use a half-integral coefficient, you might die. I tend to find the stoichiometry of the FORMER reaction a bit easier to use when calculating stoichiometric equivalence. In either scenario CHARGE and MASS are balanced ABSOLUTELY....as indeed they must be if we purport to represent an actual chemical reaction.

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Answer 3

#C_3H_8 + 5O_2 → 3CO_2 +4 H_2O#

The chemical equation for this reaction is #C_3H_8 + O_2 → CO_2 + H_2O#, producing heat. To balance the equation, start by balancing #C#,
#C_3H_8 + O_2 → 3CO_2 + H_2O#
then #H#,
#C_3H_8 + O_2 → 3CO_2 +4 H_2O#
and finally #O#. Since the product side contains #(3)(2)+4(1)=10# moles of oxygen, reactant #O_2# must be multiplied by 5 to have 10 moles as well.
The balanced chemical equation would be: #C_3H_8 + 5O_2 → 3CO_2 +4 H_2O#.

Nevertheless,

if too much or too little of #O_2# is present, the equations become
#2C_3H_8+9O_2→4CO_2+2CO+8H_2O#, producing carbon monoxide (soot)

or

#C_3H_8+2O_2→3C+4H_2O# producing carbon, respectively.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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