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What is the balanced equation for the complete combustion of #C_3H_7COC_2H_5#?

Answer 1

#2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O#

Complete combustion of #C_3H_7COC_2H_5# in oxygen will produce Carbon dioxide and water. If #a,b,c,d# are the respective molecules in the balanced equation, we have

#aC_3H_7COC_2H_5+bO_2->cCO_2+dH_2O#

Lets start with #a=1#. Balancing the number of carbon on both sides we obtain #c=6#. And the equation becomes #aC_3H_7COC_2H_5+bO_2->6CO_2+6H_2O#

#C_3H_7COC_2H_5+bO_2->6CO_2+dH_2O# Now balancing hydrogen atoms we obtain #d=6#. And the equation becomes

#C_3H_7COC_2H_5+bO_2->6CO_2+6H_2O# Now balancing #O# atoms we see that it #b=17/2# Multiplying all with 2 we obtain balanced equation as

#2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O#

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Answer 2

Luna Chen

The balanced equation for the complete combustion of C3H7COC2H5 is:

C3H7COC2H5 + 9.5 O2 → 4 CO2 + 5 H2O

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.