What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -> Mg(OH)_2+NH_3#?

Answer 1

#"Mg"_ 3"N"_2(s) + 6"H"_2 "O"(l) -> 3"Mg"("OH")_2(aq) + 2"NH"_3(aq)#

The first step is to count the moles in each element separately on the left side and compare that number to the exact same number of moles for the same element on the right side.

For example, we have #"Mg"_3"N"_2# on the left side and on the right side on the original equation we see magnesium as #"Mg"("OH")_2#.
On the left side, there are 3 moles of #"Mg"#. Now making sure we have exactly 3 moles of #"Mg"# on the right side, we add a #3# in front of the compound #"Mg"("OH")_2# to make it #3"Mg"("OH")_2#. Do same for all.
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Answer 2

#Mg_3N_2(s) + 6H_2O(l)rarr3Mg(OH)_2(aq) + 2NH_3(aq)#

There are three metal atoms, two nitrogens, twelve hydrogen atoms, and six oxygen atoms on both sides of the equation. This means that the reaction at least complies with the experiment and the principle of conservation of mass. Next, you ask yourself if the reaction is mass balanced and charge balanced.

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Answer 3

3 Mg₃N₂ + 6 H₂O → 3 Mg(OH)₂ + 2 NH₃

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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