What is the axis of symmetry and vertex for the graph # y = -x^2 +4x + 3#?
We are going to use the expression to find the vertex of a parabola.
First of all, let us graph the curve:
graph{-x^2+4x+3 [-10, 10, -10, 10]}
This curve is a parabola, because of the form of its equation:
So, in our case:
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Axis of symmetry: ( x = \frac{-b}{2a} = \frac{-4}{2(-1)} = 2 )
Vertex: To find the vertex, substitute the value of ( x ) into the equation:
( y = -x^2 + 4x + 3 ) ( y = -(2)^2 + 4(2) + 3 ) ( y = -4 + 8 + 3 ) ( y = 7 )
So, the vertex is ( (2, 7) ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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