Home > Algebra > Quadratic Functions and Their Graphs

What is the axis of symmetry and vertex for the graph # y= 6x^2 +2x+4#?

Answer 1

Kennedy Adams

Vertex #(-1/6,23/6)#
Axis of symmetry #x=-1/6#

Given -

#y=6x^2+2x+4#

#x=(-b)/(2a)=(-2)/(2xx6)=-1/6#

At #x=-1/6#

#y=6(-1/6)^2+2(-1/6)+4# #y=6(1/36)-2/6+4# #y=1/6-1/3+4=(1-2+24)/6=23/6#

Vertex #(-1/6,23/6)# Axis of symmetry #x=-1/6#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Jameson Allen

To find the axis of symmetry and vertex for the graph of (y = 6x^2 + 2x + 4), you can use the formula:

Axis of symmetry: (x = \frac{-b}{2a})

Where (a = 6) and (b = 2) from the quadratic equation (y = ax^2 + bx + c).

Substitute the values of (a) and (b) into the formula to find the axis of symmetry.

Once you find the axis of symmetry ((x)-coordinate), substitute it back into the original equation to find the corresponding (y)-coordinate, which gives you the vertex of the parabola.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.