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What is the axis of symmetry and vertex for the graph #y = 4x^2 + 10x + 5#?

Answer 1

Vertex #(-5/4, -5/4)#

x-coordinate of vertex, or of the axis of symmetry: #x = -b/(2a) = -10/8 = -5/4# y-coordinate of vertex: #y(-5/4) = 4(25/16) - 10(5/4) + 5 = - 5/4# #vertex (-5/4, -5/4)# graph{4x^2 + 10x + 5 [-2.5, 2.5, -1.25, 1.25]}

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Answer 2

Eli Assouline

The axis of symmetry for the graph (y = 4x^2 + 10x + 5) is (x = -\frac{5}{4}), and the vertex is ((- \frac{5}{4}, \frac{5}{4})).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.