# What is the axis of symmetry and vertex for the graph #y=-2x^2+4x-5#?

The equation of the axis of symmetry is

When given an equation of the form,

This is, also, h; the x coordinate of the vertex:

The y coordinate of the vertex, k, is the value of the function evaluated at h:

For the given equation,

The equation of the axis of symmetry is:

This is, also, the x coordinated of vertex:

The y coordinate of the vertex is:

The vertex is

Here is a graph of, the function, the axis of symmetry, and the vertex.

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The axis of symmetry for the graph of (y = -2x^2 + 4x - 5) is given by the equation (x = \frac{-b}{2a}), where (a = -2) and (b = 4). Thus, (x = \frac{-4}{2*(-2)} = 1). To find the vertex, substitute (x = 1) into the equation (y = -2x^2 + 4x - 5). So, (y = -2(1)^2 + 4(1) - 5 = -2 + 4 - 5 = -3). Therefore, the axis of symmetry is (x = 1) and the vertex is at the point ((1, -3)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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