# What is the average rate of change of the function #f(x)=2x^2 -3x -1# on the interval [2, 2.1]?

This provides us with

Addendum:

Halfway through the interval, the derivative (rate of change) of the function should be roughly equal to the average rate of change on this interval.

The derivative of the function is

They are identical in this instance.

By signing up, you agree to our Terms of Service and Privacy Policy

The average rate of change of the function (f(x) = 2x^2 - 3x - 1) on the interval ([2, 2.1]) is approximately (0.9).

By signing up, you agree to our Terms of Service and Privacy Policy

- An object moves according to the equation #y=1/(t+2),y>=0#, how do you find the velocity as a function of t?
- What is the equation of the line tangent to # f(x)=2x^2 + cos(x)# at # x=pi/3#?
- How do you find the average rate of change of #y=x^2-x+1# over [0,3]?
- What is the instantaneous rate of change of #f(x)=1/(x^2+2x+3 )# at #x=0 #?
- What are the x and y intercepts of #y = 2x -sqrt(x^2 + 1)#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7