What is the average atomic mass of silicon?

Given the following data, calculate the average atomic mass of silicon.

isotope = Si-28
amu =27.9769
abundance(%) =92.18

isotope = Si-29
amu =28.9765
abundance(%) =4.71

isotope =Si-30
amu =29.9738
abundance(%) =3.12

Answer 1

Multiply the amu by the percentage of occurrence to arrive at an average atomic mass of #28.0891#

We obtain a weighted average by taking the amu of each isotope and multiplying it by the occurrence percentage:

#27.9769xx.9218+28.9765xx.0471+29.9738xx.0312# (quick note - there is a bit of rounding in here - the abundance percentages add up to 1.01, so the number we calculate is going to be slightly off).

This reduces to:

#25.7891+1.3648+0.9352=28.0891#

Upon consulting "the internet" to confirm our response, I discovered 28.0855 u ± 0.0003 u; thus, the result computed for our query is fairly accurate.

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Answer 2

About 28.0855 atomic mass units (amu) make up the average atomic mass of silicon.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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