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What is the area of the parallelogram with the given vertices? A(-1, 3), B(0, 4), C(2, 2), D(1, 1)

Answer 1

Theodore Abad

The length BC: #(0-2)^2+(4-2)^2=BC^2#

#4+4=BC^2#

#BC=sqrt8#

The length DC: #(1-2)^2+(1-2)^2=DC^2#

#1+1=DC^2#

#DC=sqrt2#

area=#sqrt8xxsqrt2=sqrt16=4#

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Answer 2

Theodore Abad

To find the area of the parallelogram with the given vertices, you can use the formula:

Area = |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)| / 2

Substitute the coordinates of the vertices into the formula:

Area = |-1(4 - 2) + 0(2 - 3) + 2(3 - 1) + 1(1 - 4)| / 2 = |(-1)(2) + (0)(-1) + 2(2) + (1)(-3)| / 2 = |-2 + 0 + 4 - 3| / 2 = |(-2) + 1| / 2 = 1 / 2 = 0.5 square units

So, the area of the parallelogram is 0.5 square units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.