What is the area of a triangle with the vertices at (-1,-1) , (3,-1) . and (2,2)?

Question

Eli Assouline · Accepted Answer

Use:
#(text{Area of triangle}) = ((height)( base)) / 2#
Plot the coordinates out on a piece of graph paper. It can then be seen that height=3 and base=4, therefore the area is 6.

Use: #(text{Area of triangle}) = ((height)( base)) / 2# Plot the coordinates out on a piece of graph paper. It can then be seen that height=3 and base=4, therefore the area is 6.

You don't even need to plot them out as the height is the difference in the y coordinates: height = 2 - (-1) = 3.

The length of the base is the difference in the x coordinates of the two lower vertices, (-1,-1) and (3,-1): base = 3 - (-1) = 4

Thus: Area = #((3)(4))/2 = 12/2 = 6#

Savannah Anderson · Answer

undefined To find the area of a triangle with vertices at (-1,-1), (3,-1), and (2,2), you can use the formula for the area of a triangle given the coordinates of its vertices:

Area = |(x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)) / 2|

Substituting the coordinates:

Area = |(-1(2 - (-1)) + 3(2 - (-1)) + 2((-1) - 2)) / 2|

Area = |(-1(3) + 3(3) + 2(-3)) / 2|

Area = |(-3 + 9 - 6) / 2|

Area = |0|

Therefore, the area of the triangle is 0 square units.