What is the area of a trapezoid with bases 2ft and 3ft and height 1/4ft?

Answer 1

#A=5/8" ft"^2#

#A_"trapezoid"=(h(b_1+b_2))/2#
#A=(1/4(2+3))/2#
#A=(5/4)/2#
#A=5/8" ft"^2#
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Answer 2

To find the area ( A ) of a trapezoid, you can use the formula:

[ A = \frac{1}{2} \times \text{height} \times (\text{base}_1 + \text{base}_2) ]

Substitute the given values:

[ A = \frac{1}{2} \times \frac{1}{4} \times (2 + 3) ]

Simplify and calculate the area:

[ A = \frac{1}{2} \times \frac{1}{4} \times 5 ]

[ A = \frac{5}{8} \text{ square feet} ]

Therefore, the area of the trapezoid is ( \frac{5}{8} ) square feet.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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