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What is the area of a parallelogram with the given coordinates? P(2,3) Q(4,3) R(-2,-5) S(-4,-5)

Answer 1

James Atkins

#16#

#PQ: y = 3#

#RS: y = -5#

Area#(PQRS) = |RS| * h = 2 * dist(PQ, RS) = 2 * 8#

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Answer 2

Parker Allen

To find the area of a parallelogram with the given coordinates, you can use the formula:

Area = |(x1y2 + x2y3 + x3y4 + x4y1) - (y1x2 + y2x3 + y3x4 + y4x1)| / 2

Substitute the coordinates into the formula:

x1 = 2, y1 = 3 x2 = 4, y2 = 3 x3 = -2, y3 = -5 x4 = -4, y4 = -5

Area = |(2 * 3 + 4 * -5 + -2 * -5 + -4 * 3) - (3 * 4 + 3 * -2 + -5 * -4 + -5 * 2)| / 2

Area = |(6 - 20 + 10 - 12) - (12 - 6 + 20 - 10)| / 2

Area = |(-16 + 10) - (16 + 6)| / 2

Area = |-6 - 22| / 2

Area = |-28| / 2

Area = 28 / 2

Area = 14 square units

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.