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What is the approximate distance between points (-7,2) and (11, -5)?

Answer 1

19.3(approx)

we know distance between A(x1,y1) and B(x2,y2) is#sqrt[(x2-x1)^2 + (y2-y1)^2] #. hence distance between (-7,2), (11, -5) is #sqrt[{11-(-7)}^2 +{(-5)-2}^2]# = #sqrt[{11+7}^2 +{-5-2}^2]# = #sqrt[18^2+7^2]# = #sqrt[324+49] = sqrt373# = 19.3 (approx)

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Answer 2

Theodore Abad

To find the approximate distance between points ((-7, 2)) and ((11, -5)), you can use the distance formula:

[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Substitute the coordinates:

[ d = \sqrt{(11 - (-7))^2 + (-5 - 2)^2} ]

[ d = \sqrt{(11 + 7)^2 + (-5 - 2)^2} ]

[ d = \sqrt{18^2 + (-7)^2} ]

[ d = \sqrt{324 + 49} ]

[ d = \sqrt{373} ]

Approximating the square root of 373:

[ d \approx \sqrt{373} \approx 19.313 ]

So, the approximate distance between the points ((-7, 2)) and ((11, -5)) is approximately 19.313 units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.