What is the antiderivative of #(x-2)sinx#?
do an IBP
By signing up, you agree to our Terms of Service and Privacy Policy
The antiderivative of (x-2)sin(x) is -xcos(x) - 2sin(x) + C, where C is the constant of integration.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you evaluate the definite integral #int (x-x^3)dx# from [0,1]?
- How do you find the integral of #(x^4+x-4) / (x^2+2)#?
- How do you find the partial sum of #Sigma (2n-1)# from n=1 to 400?
- How do you differentiate #G(x) = intsqrtt sint dt# from #sqrt(x)# to #x^3#?
- How do you evaluate the integral of #int ln(1+x^3)dx#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7