# What is the antiderivative of #sqrt(sinx)#?

This is an advanced kind of antiderivative.

No. I can't explain that.

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The antiderivative of ( \sqrt{\sin(x)} ) with respect to ( x ) cannot be expressed in terms of elementary functions. Therefore, it does not have a simple closed-form expression using standard functions like polynomials, exponentials, trigonometric functions, and logarithms.

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