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What is the antiderivative of #sin(8(pi)x)dx#?

Answer 1

Cameron Alexander

#-1/(8pi)cos(8pix) +C#

From our experience with finding derivative, we would expect the anti derivative to involve #cos(8pix)#

But the derivative of #cos(8pix)# is

#d/dx(cos(8pix)) = -sin(8pix) * d/dx(8pix)#

# = -sin(8pix) * (8pi)#

# = -8pisin(8pix)#.

This is a constant multiple of the function we started with.

We can "correct" this by starting with

#-1/(8pi)cos(8pix)#

Now the derivative is:

#d/dx(-1/(8pi)cos(8pix)) = -1/(8pi) d/dx(cos(8pix)) #

# = -1/(8pi) [-sin(8pix) * (8pi)]#

# = sin(8pix)# And don't forget the constant!

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Answer 2

Evelyn Agard

The antiderivative of sin(8πx) dx is (-1/8π) cos(8πx) + C, where C is the constant of integration.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.