What is the antiderivative of # (2x)(sinx)(cosx)#?
Christopher AgrestaWe have that
#int (2x)(sinx)(cosx)dx=int xsin2xdx= -1/2 int x (cos2x)'dx=-1/2[xcos2x-intcos2xdx]= -1/2xcos2x+1/4*sin2x+c#
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Emma AldridgeThe antiderivative of (2x)(sinx)(cosx) is 2(x^2)(sinx) + C, where C is the constant of integration.
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Samantha AdkisonThe antiderivative of (2x)(sinx)(cosx) is:
∫(2x)(sinx)(cosx) dx = sin^2(x) + C
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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