What is my theoretical yield of sodium oxide if I start with 20 grams calcium oxide in the reaction #2NaCl + CaO - CaCl_2 + Na_2O#?

Question

What is my theoretical yield of sodium oxide if I start with 20 grams calcium oxide in the reaction #2NaCl + CaO -> CaCl_2 + Na_2O#?

Luna Chen · Accepted Answer

Approx. 20 g of #Na_2O# could be isolated.

#2NaCl + CaO rarr CaCl_2 + Na_2O# #"Moles of calcium oxide"# #=# #(20*g)/(56.08*g*mol^-1)=0.357*mol.# Given the stoichiometric equation, which you have kindly provided, clearly, at most, I can get an equivalent quantity of #"natrium oxide"#. Thus, we get the following by multiplying the molar quantity by the molar mass of natrium oxide: #0.357*molxx61.98*g*mol^-1=??g#

Cooper Anderson · Answer

undefined To calculate the theoretical yield of sodium oxide (Na2O), you first need to determine the molar mass of calcium oxide (CaO), which is 56.08 g/mol. Then, use stoichiometry to find the molar ratio between calcium oxide (CaO) and sodium oxide (Na2O), which is 1:1. Finally, calculate the theoretical yield using the formula:

Theoretical yield (Na2O) = (mass of CaO / molar mass of CaO) * (molar mass of Na2O / molar mass of CaO)

The molar mass of Na2O is 61.98 g/mol.

The theoretical yield of Na2O is (20 g / 56.08 g/mol) * (61.98 g/mol / 56.08 g/mol) ≈ 21.99 grams.

What is my theoretical yield of sodium oxide if I start with 20 grams calcium oxide in the reaction #2NaCl + CaO -&gt; CaCl_2 + Na_2O#?

What is my theoretical yield of sodium oxide if I start with 20 grams calcium oxide in the reaction #2NaCl + CaO -> CaCl_2 + Na_2O#?