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What is #log_6 496.8 - log_6 2.3#?

Answer 1

Sophie Adams

I found that it is equal to #3#

We can write it as: #log_6(496.8/2.3)=log_6(216)=3#

We use the property of logs: #loga-logb=log(a/b)# and the definition of log: #log_ax=b ->a^b=x# in: #log_6(216)=3#

because: #6^3=216#

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Answer 2

Liam Brennan

log_6 496.8 - log_6 2.3 is equal to approximately 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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