# What is #lim_(xrarroo) (e^(2x)sin(1/x))/x^2 #?

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Additional Clarification

This is the logic that produced the previously mentioned solution.

Since this is an indeterminate form, l'Hospital's Rule is not applicable.

This is what drives the rewriting that was done earlier.

If you don't have access to this information, apply L'Hospital's rule to determine

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The limit of (e^(2x)sin(1/x))/x^2 as x approaches infinity is 0.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How do you find the limit of #sqrt(x^2-9)/(2x-6)# as #x->oo#?
- Evaluate the limit of the indeterminate quotient?
- How do you find the limit of #sin(x+4sinx)# as x approaches pi?

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