What is #int tan^3(2x) sec^100(2x) dx#?
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To integrate ( \tan^3(2x) \sec^{100}(2x) , dx ), we can use the substitution method:
Let ( u = \tan(2x) ), then ( du = 2\sec^2(2x) , dx ).
This means that ( dx = \frac{1}{2\sec^2(2x)} , du = \frac{1}{2(u^2 + 1)} , du ).
Substituting these into the integral:
[ \int \tan^3(2x) \sec^{100}(2x) , dx = \int u^3 \sec^{100}(2x) \cdot \frac{1}{2(u^2 + 1)} , du ]
[ = \frac{1}{2} \int \frac{u^3}{(u^2 + 1)^{100}} , du ]
Now, you can integrate this using standard techniques, such as partial fractions or possibly another method depending on the complexity of the integral.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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