# What is #int 4 x^5 -7 x^4 + 3 x^3 -8 x^2 -4 x + 1 dx#?

Use the power rule in reverse:

Thus, the antiderivative of the function is

which simplifies to be

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The integral of (4x^5 - 7x^4 + 3x^3 - 8x^2 - 4x + 1) with respect to (x) is:

[ \frac{4}{6}x^6 - \frac{7}{5}x^5 + \frac{3}{4}x^4 - \frac{8}{3}x^3 - 2x^2 + \frac{1}{2}x^2 + C ]

where (C) is the constant of integration.

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