# What is #int 1/(t^2-9)^(1/2)dt#?

thus, integration turns into

that is a typical integral

as in

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The integral of ( \frac{1}{\sqrt{t^2 - 9}} ) with respect to ( t ) is ( \sinh^{-1}\left(\frac{t}{3}\right) + C ), where ( C ) is the constant of integration.

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