# What is #f(x) = int (3x-2)^2-5x+1 dx# if #f(2) = 1 #?

The indefinite integral is

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To find ( f(x) ), integrate the given function ( \int (3x-2)^2 - 5x + 1 , dx ) with respect to ( x ), then use the given condition ( f(2) = 1 ) to solve for the constant of integration.

Given that ( f(2) = 1 ), substitute ( x = 2 ) into the function and solve for the constant of integration.

[ f(2) = \int_{c}^{2} (3x-2)^2 - 5x + 1 , dx = 1 ]

After solving the integral, you'll have ( f(x) ).

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